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x^{2}=\frac{3}{5}
Divide both sides by 5.
x=\frac{\sqrt{15}}{5} x=-\frac{\sqrt{15}}{5}
Take the square root of both sides of the equation.
x^{2}=\frac{3}{5}
Divide both sides by 5.
x^{2}-\frac{3}{5}=0
Subtract \frac{3}{5} from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{3}{5}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{3}{5} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{3}{5}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{\frac{12}{5}}}{2}
Multiply -4 times -\frac{3}{5}.
x=\frac{0±\frac{2\sqrt{15}}{5}}{2}
Take the square root of \frac{12}{5}.
x=\frac{\sqrt{15}}{5}
Now solve the equation x=\frac{0±\frac{2\sqrt{15}}{5}}{2} when ± is plus.
x=-\frac{\sqrt{15}}{5}
Now solve the equation x=\frac{0±\frac{2\sqrt{15}}{5}}{2} when ± is minus.
x=\frac{\sqrt{15}}{5} x=-\frac{\sqrt{15}}{5}
The equation is now solved.