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5x^{2}+9-6x^{2}<7x
Subtract 6x^{2} from both sides.
-x^{2}+9<7x
Combine 5x^{2} and -6x^{2} to get -x^{2}.
-x^{2}+9-7x<0
Subtract 7x from both sides.
x^{2}-9+7x>0
Multiply the inequality by -1 to make the coefficient of the highest power in -x^{2}+9-7x positive. Since -1 is negative, the inequality direction is changed.
x^{2}-9+7x=0
To solve the inequality, factor the left hand side. Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-7±\sqrt{7^{2}-4\times 1\left(-9\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 7 for b, and -9 for c in the quadratic formula.
x=\frac{-7±\sqrt{85}}{2}
Do the calculations.
x=\frac{\sqrt{85}-7}{2} x=\frac{-\sqrt{85}-7}{2}
Solve the equation x=\frac{-7±\sqrt{85}}{2} when ± is plus and when ± is minus.
\left(x-\frac{\sqrt{85}-7}{2}\right)\left(x-\frac{-\sqrt{85}-7}{2}\right)>0
Rewrite the inequality by using the obtained solutions.
x-\frac{\sqrt{85}-7}{2}<0 x-\frac{-\sqrt{85}-7}{2}<0
For the product to be positive, x-\frac{\sqrt{85}-7}{2} and x-\frac{-\sqrt{85}-7}{2} have to be both negative or both positive. Consider the case when x-\frac{\sqrt{85}-7}{2} and x-\frac{-\sqrt{85}-7}{2} are both negative.
x<\frac{-\sqrt{85}-7}{2}
The solution satisfying both inequalities is x<\frac{-\sqrt{85}-7}{2}.
x-\frac{-\sqrt{85}-7}{2}>0 x-\frac{\sqrt{85}-7}{2}>0
Consider the case when x-\frac{\sqrt{85}-7}{2} and x-\frac{-\sqrt{85}-7}{2} are both positive.
x>\frac{\sqrt{85}-7}{2}
The solution satisfying both inequalities is x>\frac{\sqrt{85}-7}{2}.
x<\frac{-\sqrt{85}-7}{2}\text{; }x>\frac{\sqrt{85}-7}{2}
The final solution is the union of the obtained solutions.