Solve for x
x=\frac{\sqrt{129}-7}{10}\approx 0.435781669
x=\frac{-\sqrt{129}-7}{10}\approx -1.835781669
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5x^{2}+7x-4=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-7±\sqrt{7^{2}-4\times 5\left(-4\right)}}{2\times 5}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 5 for a, 7 for b, and -4 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-7±\sqrt{49-4\times 5\left(-4\right)}}{2\times 5}
Square 7.
x=\frac{-7±\sqrt{49-20\left(-4\right)}}{2\times 5}
Multiply -4 times 5.
x=\frac{-7±\sqrt{49+80}}{2\times 5}
Multiply -20 times -4.
x=\frac{-7±\sqrt{129}}{2\times 5}
Add 49 to 80.
x=\frac{-7±\sqrt{129}}{10}
Multiply 2 times 5.
x=\frac{\sqrt{129}-7}{10}
Now solve the equation x=\frac{-7±\sqrt{129}}{10} when ± is plus. Add -7 to \sqrt{129}.
x=\frac{-\sqrt{129}-7}{10}
Now solve the equation x=\frac{-7±\sqrt{129}}{10} when ± is minus. Subtract \sqrt{129} from -7.
x=\frac{\sqrt{129}-7}{10} x=\frac{-\sqrt{129}-7}{10}
The equation is now solved.
5x^{2}+7x-4=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
5x^{2}+7x-4-\left(-4\right)=-\left(-4\right)
Add 4 to both sides of the equation.
5x^{2}+7x=-\left(-4\right)
Subtracting -4 from itself leaves 0.
5x^{2}+7x=4
Subtract -4 from 0.
\frac{5x^{2}+7x}{5}=\frac{4}{5}
Divide both sides by 5.
x^{2}+\frac{7}{5}x=\frac{4}{5}
Dividing by 5 undoes the multiplication by 5.
x^{2}+\frac{7}{5}x+\left(\frac{7}{10}\right)^{2}=\frac{4}{5}+\left(\frac{7}{10}\right)^{2}
Divide \frac{7}{5}, the coefficient of the x term, by 2 to get \frac{7}{10}. Then add the square of \frac{7}{10} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+\frac{7}{5}x+\frac{49}{100}=\frac{4}{5}+\frac{49}{100}
Square \frac{7}{10} by squaring both the numerator and the denominator of the fraction.
x^{2}+\frac{7}{5}x+\frac{49}{100}=\frac{129}{100}
Add \frac{4}{5} to \frac{49}{100} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x+\frac{7}{10}\right)^{2}=\frac{129}{100}
Factor x^{2}+\frac{7}{5}x+\frac{49}{100}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{7}{10}\right)^{2}}=\sqrt{\frac{129}{100}}
Take the square root of both sides of the equation.
x+\frac{7}{10}=\frac{\sqrt{129}}{10} x+\frac{7}{10}=-\frac{\sqrt{129}}{10}
Simplify.
x=\frac{\sqrt{129}-7}{10} x=\frac{-\sqrt{129}-7}{10}
Subtract \frac{7}{10} from both sides of the equation.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}