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5\sqrt[3]{3}+125\sqrt{24}-6\sqrt[3]{81}
Calculate 5 to the power of 3 and get 125.
5\sqrt[3]{3}+125\times 2\sqrt{6}-6\sqrt[3]{81}
Factor 24=2^{2}\times 6. Rewrite the square root of the product \sqrt{2^{2}\times 6} as the product of square roots \sqrt{2^{2}}\sqrt{6}. Take the square root of 2^{2}.
5\sqrt[3]{3}+250\sqrt{6}-6\sqrt[3]{81}
Multiply 125 and 2 to get 250.