Solve for x
x=\frac{3\left(y+1\right)}{5}
Solve for y
y=\frac{5x}{3}-1
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5x-3y=3
Multiply both sides of the equation by 3.
5x=3+3y
Add 3y to both sides.
5x=3y+3
The equation is in standard form.
\frac{5x}{5}=\frac{3y+3}{5}
Divide both sides by 5.
x=\frac{3y+3}{5}
Dividing by 5 undoes the multiplication by 5.
5x-3y=3
Multiply both sides of the equation by 3.
-3y=3-5x
Subtract 5x from both sides.
\frac{-3y}{-3}=\frac{3-5x}{-3}
Divide both sides by -3.
y=\frac{3-5x}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{5x}{3}-1
Divide 3-5x by -3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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