Solve 57/8-25/9+1.125-34/9

$$5 \frac { 7 } { 8 } - 2 \frac { 5 } { 9 } + 1.125 - 3 \frac { 4 } { 9 }$$

Evaluate

$$1$$

Solution Steps

Multiply 5 and 8 to get 40.

$$\frac{40+7}{8}-\frac{2\times 9+5}{9}+1.125-\frac{3\times 9+4}{9}$$

Add 40 and 7 to get 47.

$$\frac{47}{8}-\frac{2\times 9+5}{9}+1.125-\frac{3\times 9+4}{9}$$

Multiply 2 and 9 to get 18.

$$\frac{47}{8}-\frac{18+5}{9}+1.125-\frac{3\times 9+4}{9}$$

Add 18 and 5 to get 23.

$$\frac{47}{8}-\frac{23}{9}+1.125-\frac{3\times 9+4}{9}$$

Least common multiple of 8 and 9 is 72. Convert \frac{47}{8} and \frac{23}{9} to fractions with denominator 72.

$$\frac{423}{72}-\frac{184}{72}+1.125-\frac{3\times 9+4}{9}$$

Since \frac{423}{72} and \frac{184}{72} have the same denominator, subtract them by subtracting their numerators.

$$\frac{423-184}{72}+1.125-\frac{3\times 9+4}{9}$$

Subtract 184 from 423 to get 239.

$$\frac{239}{72}+1.125-\frac{3\times 9+4}{9}$$

Convert decimal number 1.125 to fraction \frac{1125}{1000}. Reduce the fraction \frac{1125}{1000} to lowest terms by extracting and canceling out 125.

$$\frac{239}{72}+\frac{9}{8}-\frac{3\times 9+4}{9}$$

Least common multiple of 72 and 8 is 72. Convert \frac{239}{72} and \frac{9}{8} to fractions with denominator 72.

$$\frac{239}{72}+\frac{81}{72}-\frac{3\times 9+4}{9}$$

Since \frac{239}{72} and \frac{81}{72} have the same denominator, add them by adding their numerators.

$$\frac{239+81}{72}-\frac{3\times 9+4}{9}$$

Add 239 and 81 to get 320.

$$\frac{320}{72}-\frac{3\times 9+4}{9}$$

Reduce the fraction \frac{320}{72} to lowest terms by extracting and canceling out 8.

$$\frac{40}{9}-\frac{3\times 9+4}{9}$$

Multiply 3 and 9 to get 27.

$$\frac{40}{9}-\frac{27+4}{9}$$

Add 27 and 4 to get 31.

$$\frac{40}{9}-\frac{31}{9}$$

Since \frac{40}{9} and \frac{31}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{40-31}{9}$$

Subtract 31 from 40 to get 9.

$$\frac{9}{9}$$

Divide 9 by 9 to get 1.

$$1$$

Factor

$$1$$