Solve 51/3+41/6=

$$5 \frac { 1 } { 3 } + 4 \frac { 1 } { 6 } =$$

Evaluate

$$\frac{19}{2}=9.5$$

Solution Steps

Multiply 5 and 3 to get 15.

$$\frac{15+1}{3}+\frac{4\times 6+1}{6}$$

Add 15 and 1 to get 16.

$$\frac{16}{3}+\frac{4\times 6+1}{6}$$

Multiply 4 and 6 to get 24.

$$\frac{16}{3}+\frac{24+1}{6}$$

Add 24 and 1 to get 25.

$$\frac{16}{3}+\frac{25}{6}$$

Least common multiple of 3 and 6 is 6. Convert \frac{16}{3} and \frac{25}{6} to fractions with denominator 6.

$$\frac{32}{6}+\frac{25}{6}$$

Since \frac{32}{6} and \frac{25}{6} have the same denominator, add them by adding their numerators.

$$\frac{32+25}{6}$$

Add 32 and 25 to get 57.

$$\frac{57}{6}$$

Reduce the fraction \frac{57}{6} to lowest terms by extracting and canceling out 3.

$$\frac{19}{2}$$

Factor

$$\frac{19}{2} = 9\frac{1}{2} = 9.5$$