Solve 5*[2^3+(-7)*2-(1-6)]

$$5 \cdot [ 2 ^ { 3 } + ( - 7 ) \cdot 2 - ( 1 - 6 ) ]$$

Evaluate

$$-5$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$5\left(8-7\times 2-\left(1-6\right)\right)$$

Multiply -7 and 2 to get -14.

$$5\left(8-14-\left(1-6\right)\right)$$

Subtract 14 from 8 to get -6.

$$5\left(-6-\left(1-6\right)\right)$$

Subtract 6 from 1 to get -5.

$$5\left(-6-\left(-5\right)\right)$$

The opposite of -5 is 5.

$$5\left(-6+5\right)$$

Add -6 and 5 to get -1.

$$5\left(-1\right)$$

Multiply 5 and -1 to get -5.

$$-5$$

Factor

$$-5$$