Solve 5*10+1/2-0.510^2

$$5 \cdot 10+ \frac{ 1 }{ 2 } -0.5 { 10 }^{ 2 }$$

Evaluate

$$0.5$$

Solution Steps

Multiply 5 and 10 to get 50.

$$50+\frac{1}{2}-0.5\times 10^{2}$$

Convert 50 to fraction \frac{100}{2}.

$$\frac{100}{2}+\frac{1}{2}-0.5\times 10^{2}$$

Since \frac{100}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{100+1}{2}-0.5\times 10^{2}$$

Add 100 and 1 to get 101.

$$\frac{101}{2}-0.5\times 10^{2}$$

Calculate 10 to the power of 2 and get 100.

$$\frac{101}{2}-0.5\times 100$$

Multiply 0.5 and 100 to get 50.

$$\frac{101}{2}-50$$

Convert 50 to fraction \frac{100}{2}.

$$\frac{101}{2}-\frac{100}{2}$$

Since \frac{101}{2} and \frac{100}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{101-100}{2}$$

Subtract 100 from 101 to get 1.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$