Solve 5^x+4=3

$$5 ^ { x + 4 } = 3$$

Solve for x

$$x=\log_{5}\left(3\right)-4\approx -3.317393806$$

Steps Using Definition of Logarithm

Use the rules of exponents and logarithms to solve the equation.

$$5^{x+4}=3$$

Take the logarithm of both sides of the equation.

$$\log(5^{x+4})=\log(3)$$

The logarithm of a number raised to a power is the power times the logarithm of the number.

$$\left(x+4\right)\log(5)=\log(3)$$

Divide both sides by \log(5).

$$x+4=\frac{\log(3)}{\log(5)}$$

By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x+4=\log_{5}\left(3\right)$$

Subtract 4 from both sides of the equation.

$$x=\log_{5}\left(3\right)-4$$

Solve for x (complex solution)

$$x=\frac{i\times 2\pi n_{1}}{\ln(5)}+\log_{5}\left(3\right)-4$$

$$n_{1}\in \mathrm{Z}$$