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5^{n-3}=\frac{1}{25}
Use the rules of exponents and logarithms to solve the equation.
\log(5^{n-3})=\log(\frac{1}{25})
Take the logarithm of both sides of the equation.
\left(n-3\right)\log(5)=\log(\frac{1}{25})
The logarithm of a number raised to a power is the power times the logarithm of the number.
n-3=\frac{\log(\frac{1}{25})}{\log(5)}
Divide both sides by \log(5).
n-3=\log_{5}\left(\frac{1}{25}\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
n=-2-\left(-3\right)
Add 3 to both sides of the equation.