Solve 5^0-sqrt{3^2}+1^10-4*2=

$$5 ^ { 0 } - \sqrt { 3 ^ { 2 } } + 1 ^ { 10 } - 4 \times 2 =$$

Evaluate

$$-9$$

Solution Steps

Calculate 5 to the power of 0 and get 1.

$$1-\sqrt{3^{2}}+1^{10}-4\times 2$$

Calculate 3 to the power of 2 and get 9.

$$1-\sqrt{9}+1^{10}-4\times 2$$

Calculate the square root of 9 and get 3.

$$1-3+1^{10}-4\times 2$$

Subtract 3 from 1 to get -2.

$$-2+1^{10}-4\times 2$$

Calculate 1 to the power of 10 and get 1.

$$-2+1-4\times 2$$

Add -2 and 1 to get -1.

$$-1-4\times 2$$

Multiply 4 and 2 to get 8.

$$-1-8$$

Subtract 8 from -1 to get -9.

$$-9$$

Factor

$$-9$$