Solve 5=x_{1}+x_{1}+45x

$$5 = x _ { 1 } + x _ { 1 } + 45 x$$

Solve for x

$$x=-\frac{2x_{1}}{45}+\frac{1}{9}$$

Steps for Solving Linear Equation

Combine x_{1} and x_{1} to get 2x_{1}.

$$5=2x_{1}+45x$$

Swap sides so that all variable terms are on the left hand side.

$$2x_{1}+45x=5$$

Subtract 2x_{1} from both sides.

$$45x=5-2x_{1}$$

Divide both sides by 45.

$$\frac{45x}{45}=\frac{5-2x_{1}}{45}$$

Dividing by 45 undoes the multiplication by 45.

$$x=\frac{5-2x_{1}}{45}$$

Divide -2x_{1}+5 by 45.

$$x=-\frac{2x_{1}}{45}+\frac{1}{9}$$

Solve for x_1

$$x_{1}=\frac{5-45x}{2}$$

Steps for Solving Linear Equation

Combine x_{1} and x_{1} to get 2x_{1}.

$$5=2x_{1}+45x$$

Swap sides so that all variable terms are on the left hand side.

$$2x_{1}+45x=5$$

Subtract 45x from both sides.

$$2x_{1}=5-45x$$

Divide both sides by 2.

$$\frac{2x_{1}}{2}=\frac{5-45x}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x_{1}=\frac{5-45x}{2}$$