Solve 5=a(-5)^2+b(-5)+18

$$5 = a ( - 5 ) ^ { 2 } + b ( - 5 ) + 18$$

Solve for a

$$a=\frac{b}{5}-\frac{13}{25}$$

Steps for Solving Linear Equation

Calculate -5 to the power of 2 and get 25.

$$5=a\times 25+b\left(-5\right)+18$$

Swap sides so that all variable terms are on the left hand side.

$$a\times 25+b\left(-5\right)+18=5$$

Subtract b\left(-5\right) from both sides.

$$a\times 25+18=5-b\left(-5\right)$$

Subtract 18 from both sides.

$$a\times 25=5-b\left(-5\right)-18$$

Multiply -1 and -5 to get 5.

$$a\times 25=5+5b-18$$

Subtract 18 from 5 to get -13.

$$a\times 25=-13+5b$$

The equation is in standard form.

$$25a=5b-13$$

Divide both sides by 25.

$$\frac{25a}{25}=\frac{5b-13}{25}$$

Dividing by 25 undoes the multiplication by 25.

$$a=\frac{5b-13}{25}$$

Divide -13+5b by 25.

$$a=\frac{b}{5}-\frac{13}{25}$$

Solve for b

$$b=5a+\frac{13}{5}$$

Steps for Solving Linear Equation

Calculate -5 to the power of 2 and get 25.

$$5=a\times 25+b\left(-5\right)+18$$

Swap sides so that all variable terms are on the left hand side.

$$a\times 25+b\left(-5\right)+18=5$$

Subtract a\times 25 from both sides.

$$b\left(-5\right)+18=5-a\times 25$$

Subtract 18 from both sides.

$$b\left(-5\right)=5-a\times 25-18$$

Multiply -1 and 25 to get -25.

$$b\left(-5\right)=5-25a-18$$

Subtract 18 from 5 to get -13.

$$b\left(-5\right)=-13-25a$$

The equation is in standard form.

$$-5b=-25a-13$$

Divide both sides by -5.

$$\frac{-5b}{-5}=\frac{-25a-13}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$b=\frac{-25a-13}{-5}$$

Divide -13-25a by -5.

$$b=5a+\frac{13}{5}$$