Solve 5=9/4+12-pj^2

$$5 = \frac { 9 } { 4 } + 12 - p j ^ { 2 }$$

Solve for p

$$p=\frac{37}{4j^{2}}$$

$$j\neq 0$$

Steps for Solving Linear Equation

Add \frac{9}{4} and 12 to get \frac{57}{4}.

$$5=\frac{57}{4}-pj^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{57}{4}-pj^{2}=5$$

Subtract \frac{57}{4} from both sides.

$$-pj^{2}=5-\frac{57}{4}$$

Subtract \frac{57}{4} from 5 to get -\frac{37}{4}.

$$-pj^{2}=-\frac{37}{4}$$

The equation is in standard form.

$$\left(-j^{2}\right)p=-\frac{37}{4}$$

Divide both sides by -j^{2}.

$$\frac{\left(-j^{2}\right)p}{-j^{2}}=-\frac{\frac{37}{4}}{-j^{2}}$$

Dividing by -j^{2} undoes the multiplication by -j^{2}.

$$p=-\frac{\frac{37}{4}}{-j^{2}}$$

Divide -\frac{37}{4} by -j^{2}.

$$p=\frac{37}{4j^{2}}$$

Solve for j

$$j=\frac{\sqrt{\frac{37}{p}}}{2}$$

$$j=-\frac{\sqrt{\frac{37}{p}}}{2}\text{, }p>0$$