Solve for n
n=3
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5+n+\frac{1}{3}n=9
Add \frac{1}{3}n to both sides.
5+\frac{4}{3}n=9
Combine n and \frac{1}{3}n to get \frac{4}{3}n.
\frac{4}{3}n=9-5
Subtract 5 from both sides.
\frac{4}{3}n=4
Subtract 5 from 9 to get 4.
n=4\times \frac{3}{4}
Multiply both sides by \frac{3}{4}, the reciprocal of \frac{4}{3}.
n=3
Cancel out 4 and 4.
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