Solve for y
y=\frac{z}{4}-\frac{5}{32}
Solve for z
z=4y+\frac{5}{8}
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32y=8z-5
Subtract 5 from both sides.
\frac{32y}{32}=\frac{8z-5}{32}
Divide both sides by 32.
y=\frac{8z-5}{32}
Dividing by 32 undoes the multiplication by 32.
y=\frac{z}{4}-\frac{5}{32}
Divide 8z-5 by 32.
8z=5+32y
Swap sides so that all variable terms are on the left hand side.
8z=32y+5
The equation is in standard form.
\frac{8z}{8}=\frac{32y+5}{8}
Divide both sides by 8.
z=\frac{32y+5}{8}
Dividing by 8 undoes the multiplication by 8.
z=4y+\frac{5}{8}
Divide 5+32y by 8.
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