Solve 5+((3/5)(-7))-(-1-8)

$$5 + ( ( 3 / 5 ) ( - 7 ) ) - ( - 1 - 8 )$$

Evaluate

$$\frac{49}{5}=9.8$$

Solution Steps

Express \frac{3}{5}\left(-7\right) as a single fraction.

$$5+\frac{3\left(-7\right)}{5}-\left(-1-8\right)$$

Multiply 3 and -7 to get -21.

$$5+\frac{-21}{5}-\left(-1-8\right)$$

Fraction \frac{-21}{5} can be rewritten as -\frac{21}{5} by extracting the negative sign.

$$5-\frac{21}{5}-\left(-1-8\right)$$

Convert 5 to fraction \frac{25}{5}.

$$\frac{25}{5}-\frac{21}{5}-\left(-1-8\right)$$

Since \frac{25}{5} and \frac{21}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25-21}{5}-\left(-1-8\right)$$

Subtract 21 from 25 to get 4.

$$\frac{4}{5}-\left(-1-8\right)$$

Subtract 8 from -1 to get -9.

$$\frac{4}{5}-\left(-9\right)$$

The opposite of -9 is 9.

$$\frac{4}{5}+9$$

Convert 9 to fraction \frac{45}{5}.

$$\frac{4}{5}+\frac{45}{5}$$

Since \frac{4}{5} and \frac{45}{5} have the same denominator, add them by adding their numerators.

$$\frac{4+45}{5}$$

Add 4 and 45 to get 49.

$$\frac{49}{5}$$

Factor

$$\frac{7 ^ {2}}{5} = 9\frac{4}{5} = 9.8$$