Solve 5+41-40/2-4a/4-4a-(-20)/8=0

$$5 + \frac { 41 - 40 } { 2 } - \frac { 4 a } { 4 } - \frac { 4 a - ( - 20 ) } { 8 } = 0$$

Solve for a

$$a=2$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 8, the least common multiple of 2,4,8.

$$40+4\left(41-40\right)-2\times 4a-\left(4a-\left(-20\right)\right)=0$$

Subtract 40 from 41 to get 1.

$$40+4\times 1-2\times 4a-\left(4a-\left(-20\right)\right)=0$$

Multiply 4 and 1 to get 4.

$$40+4-2\times 4a-\left(4a-\left(-20\right)\right)=0$$

Add 40 and 4 to get 44.

$$44-2\times 4a-\left(4a-\left(-20\right)\right)=0$$

Multiply -2 and 4 to get -8.

$$44-8a-\left(4a-\left(-20\right)\right)=0$$

The opposite of -20 is 20.

$$44-8a-\left(4a+20\right)=0$$

To find the opposite of 4a+20, find the opposite of each term.

$$44-8a-4a-20=0$$

Combine -8a and -4a to get -12a.

$$44-12a-20=0$$

Subtract 20 from 44 to get 24.

$$24-12a=0$$

Subtract 24 from both sides. Anything subtracted from zero gives its negation.

$$-12a=-24$$

Divide both sides by -12.

$$a=\frac{-24}{-12}$$

Divide -24 by -12 to get 2.

$$a=2$$