Solve 4x-95=1/2(x+4x-73)

$$4x-95= \frac{ 1 }{ 2 } (x+4x-73)$$

Solve for x

$$x=39$$

Steps for Solving Linear Equation

Combine x and 4x to get 5x.

$$4x-95=\frac{1}{2}\left(5x-73\right)$$

Use the distributive property to multiply \frac{1}{2} by 5x-73.

$$4x-95=\frac{1}{2}\times 5x+\frac{1}{2}\left(-73\right)$$

Multiply \frac{1}{2} and 5 to get \frac{5}{2}.

$$4x-95=\frac{5}{2}x+\frac{1}{2}\left(-73\right)$$

Multiply \frac{1}{2} and -73 to get \frac{-73}{2}.

$$4x-95=\frac{5}{2}x+\frac{-73}{2}$$

Fraction \frac{-73}{2} can be rewritten as -\frac{73}{2} by extracting the negative sign.

$$4x-95=\frac{5}{2}x-\frac{73}{2}$$

Subtract \frac{5}{2}x from both sides.

$$4x-95-\frac{5}{2}x=-\frac{73}{2}$$

Combine 4x and -\frac{5}{2}x to get \frac{3}{2}x.

$$\frac{3}{2}x-95=-\frac{73}{2}$$

Add 95 to both sides.

$$\frac{3}{2}x=-\frac{73}{2}+95$$

Convert 95 to fraction \frac{190}{2}.

$$\frac{3}{2}x=-\frac{73}{2}+\frac{190}{2}$$

Since -\frac{73}{2} and \frac{190}{2} have the same denominator, add them by adding their numerators.

$$\frac{3}{2}x=\frac{-73+190}{2}$$

Add -73 and 190 to get 117.

$$\frac{3}{2}x=\frac{117}{2}$$

Multiply both sides by \frac{2}{3}, the reciprocal of \frac{3}{2}.

$$x=\frac{117}{2}\times \frac{2}{3}$$

Multiply \frac{117}{2} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{117\times 2}{2\times 3}$$

Cancel out 2 in both numerator and denominator.

$$x=\frac{117}{3}$$

Divide 117 by 3 to get 39.

$$x=39$$