Solve for x
x=\frac{3\left(y-8\right)}{4}
Solve for y
y=\frac{4\left(x+6\right)}{3}
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4x=-24+3y
Add 3y to both sides.
4x=3y-24
The equation is in standard form.
\frac{4x}{4}=\frac{3y-24}{4}
Divide both sides by 4.
x=\frac{3y-24}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{3y}{4}-6
Divide -24+3y by 4.
-3y=-24-4x
Subtract 4x from both sides.
-3y=-4x-24
The equation is in standard form.
\frac{-3y}{-3}=\frac{-4x-24}{-3}
Divide both sides by -3.
y=\frac{-4x-24}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{4x}{3}+8
Divide -24-4x by -3.
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Limits
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