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4x+3\sqrt{5}=2y
Add 2y to both sides. Anything plus zero gives itself.
4x=2y-3\sqrt{5}
Subtract 3\sqrt{5} from both sides.
\frac{4x}{4}=\frac{2y-3\sqrt{5}}{4}
Divide both sides by 4.
x=\frac{2y-3\sqrt{5}}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{y}{2}-\frac{3\sqrt{5}}{4}
Divide 2y-3\sqrt{5} by 4.
-2y+3\sqrt{5}=-4x
Subtract 4x from both sides. Anything subtracted from zero gives its negation.
-2y=-4x-3\sqrt{5}
Subtract 3\sqrt{5} from both sides.
\frac{-2y}{-2}=\frac{-4x-3\sqrt{5}}{-2}
Divide both sides by -2.
y=\frac{-4x-3\sqrt{5}}{-2}
Dividing by -2 undoes the multiplication by -2.
y=2x+\frac{3\sqrt{5}}{2}
Divide -4x-3\sqrt{5} by -2.