Solve 4x-x^2=x^2

$$4x- { x }^{ 2 } = { x }^{ 2 }$$

Solve for x

$$x=2$$

$$x=0$$

Steps Using Factoring

Subtract x^{2} from both sides.

$$4x-x^{2}-x^{2}=0$$

Combine -x^{2} and -x^{2} to get -2x^{2}.

$$4x-2x^{2}=0$$

Factor out x.

$$x\left(4-2x\right)=0$$

To find equation solutions, solve x=0 and 4-2x=0.

$$x=0 x=2$$

Steps Using the Quadratic Formula

Subtract x^{2} from both sides.

$$4x-x^{2}-x^{2}=0$$

Combine -x^{2} and -x^{2} to get -2x^{2}.

$$4x-2x^{2}=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$-2x^{2}+4x=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -2 for a, 4 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-4±\sqrt{4^{2}}}{2\left(-2\right)}$$

Take the square root of 4^{2}.

$$x=\frac{-4±4}{2\left(-2\right)}$$

Multiply 2 times -2.

$$x=\frac{-4±4}{-4}$$

Now solve the equation x=\frac{-4±4}{-4} when ± is plus. Add -4 to 4.

$$x=\frac{0}{-4}$$

Divide 0 by -4.

$$x=0$$

Now solve the equation x=\frac{-4±4}{-4} when ± is minus. Subtract 4 from -4.

$$x=-\frac{8}{-4}$$

Divide -8 by -4.

$$x=2$$

The equation is now solved.

$$x=0 x=2$$

Steps for Completing the Square

Subtract x^{2} from both sides.

$$4x-x^{2}-x^{2}=0$$

Combine -x^{2} and -x^{2} to get -2x^{2}.

$$4x-2x^{2}=0$$

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$-2x^{2}+4x=0$$

Divide both sides by -2.

$$\frac{-2x^{2}+4x}{-2}=\frac{0}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x^{2}+\frac{4}{-2}x=\frac{0}{-2}$$

Divide 4 by -2.

$$x^{2}-2x=\frac{0}{-2}$$

Divide 0 by -2.

$$x^{2}-2x=0$$

Divide -2, the coefficient of the x term, by 2 to get -1. Then add the square of -1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-2x+1=1$$

Factor x^{2}-2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-1\right)^{2}=1$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-1\right)^{2}}=\sqrt{1}$$

Simplify.

$$x-1=1 x-1=-1$$

Add 1 to both sides of the equation.

$$x=2 x=0$$