Solve for a (complex solution)
\left\{\begin{matrix}a=\frac{4x+b+8}{x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&x=0\text{ and }b=-8\end{matrix}\right.
Solve for a
\left\{\begin{matrix}a=\frac{4x+b+8}{x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&x=0\text{ and }b=-8\end{matrix}\right.
Solve for b
b=ax-4x-8
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ax-8=4x+b
Swap sides so that all variable terms are on the left hand side.
ax=4x+b+8
Add 8 to both sides.
xa=4x+b+8
The equation is in standard form.
\frac{xa}{x}=\frac{4x+b+8}{x}
Divide both sides by x.
a=\frac{4x+b+8}{x}
Dividing by x undoes the multiplication by x.
ax-8=4x+b
Swap sides so that all variable terms are on the left hand side.
ax=4x+b+8
Add 8 to both sides.
xa=4x+b+8
The equation is in standard form.
\frac{xa}{x}=\frac{4x+b+8}{x}
Divide both sides by x.
a=\frac{4x+b+8}{x}
Dividing by x undoes the multiplication by x.
b=ax-8-4x
Subtract 4x from both sides.
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