Solve 4x+2y-z+67=0

$$4x+2y-z+67=0$$

Solve for x

$$x=\frac{-2y+z-67}{4}$$

Steps for Solving Linear Equation

Subtract 2y from both sides. Anything subtracted from zero gives its negation.

$$4x-z+67=-2y$$

Add z to both sides.

$$4x+67=-2y+z$$

Subtract 67 from both sides.

$$4x=-2y+z-67$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{-2y+z-67}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{-2y+z-67}{4}$$

Divide -2y+z-67 by 4.

$$x=\frac{z}{4}-\frac{y}{2}-\frac{67}{4}$$

Solve for y

$$y=\frac{-4x+z-67}{2}$$

Steps for Solving Linear Equation

Subtract 4x from both sides. Anything subtracted from zero gives its negation.

$$2y-z+67=-4x$$

Add z to both sides.

$$2y+67=-4x+z$$

Subtract 67 from both sides.

$$2y=-4x+z-67$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{-4x+z-67}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{-4x+z-67}{2}$$

Divide -4x+z-67 by 2.

$$y=\frac{z}{2}-2x-\frac{67}{2}$$