Solve 4x*3x=4800

$$4x \times 3x=4800$$

Solve for x

$$x=20$$

$$x=-20$$

Steps by Finding Square Root

Multiply x and x to get x^{2}.

$$4x^{2}\times 3=4800$$

Multiply 4 and 3 to get 12.

$$12x^{2}=4800$$

Divide both sides by 12.

$$x^{2}=\frac{4800}{12}$$

Divide 4800 by 12 to get 400.

$$x^{2}=400$$

Take the square root of both sides of the equation.

$$x=20 x=-20$$

Steps Using the Quadratic Formula

Multiply x and x to get x^{2}.

$$4x^{2}\times 3=4800$$

Multiply 4 and 3 to get 12.

$$12x^{2}=4800$$

Subtract 4800 from both sides.

$$12x^{2}-4800=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 12 for a, 0 for b, and -4800 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 12\left(-4800\right)}}{2\times 12}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 12\left(-4800\right)}}{2\times 12}$$

Multiply -4 times 12.

$$x=\frac{0±\sqrt{-48\left(-4800\right)}}{2\times 12}$$

Multiply -48 times -4800.

$$x=\frac{0±\sqrt{230400}}{2\times 12}$$

Take the square root of 230400.

$$x=\frac{0±480}{2\times 12}$$

Multiply 2 times 12.

$$x=\frac{0±480}{24}$$

Now solve the equation x=\frac{0±480}{24} when ± is plus. Divide 480 by 24.

$$x=20$$

Now solve the equation x=\frac{0±480}{24} when ± is minus. Divide -480 by 24.

$$x=-20$$

The equation is now solved.

$$x=20 x=-20$$