Solve for x
x=\frac{1}{8y}
y\neq 0
Solve for y
y=\frac{1}{8x}
x\neq 0
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-8xy=-1
Multiply 4 and -2 to get -8.
\left(-8y\right)x=-1
The equation is in standard form.
\frac{\left(-8y\right)x}{-8y}=-\frac{1}{-8y}
Divide both sides by -8y.
x=-\frac{1}{-8y}
Dividing by -8y undoes the multiplication by -8y.
x=\frac{1}{8y}
Divide -1 by -8y.
-8xy=-1
Multiply 4 and -2 to get -8.
\left(-8x\right)y=-1
The equation is in standard form.
\frac{\left(-8x\right)y}{-8x}=-\frac{1}{-8x}
Divide both sides by -8x.
y=-\frac{1}{-8x}
Dividing by -8x undoes the multiplication by -8x.
y=\frac{1}{8x}
Divide -1 by -8x.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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