Solve 49x^2-10.04t-5*3=0

$$49 x ^ { 2 } - 10.04 t - 5 \cdot 3 = 0$$

Solve for t

$$t=\frac{1225x^{2}-375}{251}$$

Steps for Solving Linear Equation

Multiply 5 and 3 to get 15.

$$49x^{2}-10.04t-15=0$$

Subtract 49x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-10.04t-15=-49x^{2}$$

Add 15 to both sides.

$$-10.04t=-49x^{2}+15$$

The equation is in standard form.

$$-10.04t=15-49x^{2}$$

Divide both sides of the equation by -10.04, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{-10.04t}{-10.04}=\frac{15-49x^{2}}{-10.04}$$

Dividing by -10.04 undoes the multiplication by -10.04.

$$t=\frac{15-49x^{2}}{-10.04}$$

Divide -49x^{2}+15 by -10.04 by multiplying -49x^{2}+15 by the reciprocal of -10.04.

$$t=\frac{1225x^{2}-375}{251}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{251t+375}}{35}$$

$$x=\frac{\sqrt{251t+375}}{35}$$

Solve for x

$$x=\frac{\sqrt{251t+375}}{35}$$

$$x=-\frac{\sqrt{251t+375}}{35}\text{, }t\geq -\frac{375}{251}$$