Solve 47+48+40+50+50+57+y

$$47 + 48 + 40 + 50 + 50 + 57 + y$$

Evaluate

$$y+292$$

Solution Steps

Add 47 and 48 to get 95.

$$95+40+50+50+57+y$$

Add 95 and 40 to get 135.

$$135+50+50+57+y$$

Add 135 and 50 to get 185.

$$185+50+57+y$$

Add 185 and 50 to get 235.

$$235+57+y$$

Add 235 and 57 to get 292.

$$292+y$$

Differentiate w.r.t. y

$$1$$

Steps Using Derivative Rule for Sum

Add 47 and 48 to get 95.

$$\frac{\mathrm{d}}{\mathrm{d}y}(95+40+50+50+57+y)$$

Add 95 and 40 to get 135.

$$\frac{\mathrm{d}}{\mathrm{d}y}(135+50+50+57+y)$$

Add 135 and 50 to get 185.

$$\frac{\mathrm{d}}{\mathrm{d}y}(185+50+57+y)$$

Add 185 and 50 to get 235.

$$\frac{\mathrm{d}}{\mathrm{d}y}(235+57+y)$$

Add 235 and 57 to get 292.

$$\frac{\mathrm{d}}{\mathrm{d}y}(292+y)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$y^{1-1}$$

Subtract 1 from 1.

$$y^{0}$$

For any term t except 0, t^{0}=1.

$$1$$