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Solve for t
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Solve for t (complex solution)
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\frac{4616}{4000}=\left(1+\frac{0.098}{6}\right)^{6t}
Divide both sides by 4000.
\frac{577}{500}=\left(1+\frac{0.098}{6}\right)^{6t}
Reduce the fraction \frac{4616}{4000} to lowest terms by extracting and canceling out 8.
\frac{577}{500}=\left(1+\frac{98}{6000}\right)^{6t}
Expand \frac{0.098}{6} by multiplying both numerator and the denominator by 1000.
\frac{577}{500}=\left(1+\frac{49}{3000}\right)^{6t}
Reduce the fraction \frac{98}{6000} to lowest terms by extracting and canceling out 2.
\frac{577}{500}=\left(\frac{3049}{3000}\right)^{6t}
Add 1 and \frac{49}{3000} to get \frac{3049}{3000}.
\left(\frac{3049}{3000}\right)^{6t}=\frac{577}{500}
Swap sides so that all variable terms are on the left hand side.
\log(\left(\frac{3049}{3000}\right)^{6t})=\log(\frac{577}{500})
Take the logarithm of both sides of the equation.
6t\log(\frac{3049}{3000})=\log(\frac{577}{500})
The logarithm of a number raised to a power is the power times the logarithm of the number.
6t=\frac{\log(\frac{577}{500})}{\log(\frac{3049}{3000})}
Divide both sides by \log(\frac{3049}{3000}).
6t=\log_{\frac{3049}{3000}}\left(\frac{577}{500}\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
t=\frac{\ln(\frac{577}{500})}{6\ln(\frac{3049}{3000})}
Divide both sides by 6.