Solve 462/9-145/3-214/9=?

$$46 \frac { 2 } { 9 } - 14 \frac { 5 } { 3 } - 21 \frac { 4 } { 9 } = ?$$

Evaluate

$$\frac{82}{9}\approx 9.111111111$$

Solution Steps

Multiply 46 and 9 to get 414.

$$\frac{414+2}{9}-\frac{14\times 3+5}{3}-\frac{21\times 9+4}{9}$$

Add 414 and 2 to get 416.

$$\frac{416}{9}-\frac{14\times 3+5}{3}-\frac{21\times 9+4}{9}$$

Multiply 14 and 3 to get 42.

$$\frac{416}{9}-\frac{42+5}{3}-\frac{21\times 9+4}{9}$$

Add 42 and 5 to get 47.

$$\frac{416}{9}-\frac{47}{3}-\frac{21\times 9+4}{9}$$

Least common multiple of 9 and 3 is 9. Convert \frac{416}{9} and \frac{47}{3} to fractions with denominator 9.

$$\frac{416}{9}-\frac{141}{9}-\frac{21\times 9+4}{9}$$

Since \frac{416}{9} and \frac{141}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{416-141}{9}-\frac{21\times 9+4}{9}$$

Subtract 141 from 416 to get 275.

$$\frac{275}{9}-\frac{21\times 9+4}{9}$$

Multiply 21 and 9 to get 189.

$$\frac{275}{9}-\frac{189+4}{9}$$

Add 189 and 4 to get 193.

$$\frac{275}{9}-\frac{193}{9}$$

Since \frac{275}{9} and \frac{193}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{275-193}{9}$$

Subtract 193 from 275 to get 82.

$$\frac{82}{9}$$

Factor

$$\frac{2 \cdot 41}{3 ^ {2}} = 9\frac{1}{9} = 9.11111111111111$$