Solve 43+lceil-(36div18*2-6)+19rceil-6

$$43+ \lceil -(36 \div 18 \times 2-6)+19 \rceil -6$$

Evaluate

$$58$$

Solution Steps

Divide 36 by 18 to get 2.

$$43+\lceil -\left(2\times 2-6\right)+19\rceil -6$$

Multiply 2 and 2 to get 4.

$$43+\lceil -\left(4-6\right)+19\rceil -6$$

Subtract 6 from 4 to get -2.

$$43+\lceil -\left(-2\right)+19\rceil -6$$

The opposite of -2 is 2.

$$43+\lceil 2+19\rceil -6$$

Add 2 and 19 to get 21.

$$43+\lceil 21\rceil -6$$

The ceiling of a real number a is the smallest integer number greater than or equal to a. The ceiling of 21 is 21.

$$43+21-6$$

Add 43 and 21 to get 64.

$$64-6$$

Subtract 6 from 64 to get 58.

$$58$$

Factor

$$2\times 29$$