Factor
\left(6z-1\right)\left(7z^{2}+8\right)
Evaluate
\left(6z-1\right)\left(7z^{2}+8\right)
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\left(6z-1\right)\left(7z^{2}+8\right)
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -8 and q divides the leading coefficient 42. One such root is \frac{1}{6}. Factor the polynomial by dividing it by 6z-1. Polynomial 7z^{2}+8 is not factored since it does not have any rational roots.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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Linear equation
y = 3x + 4
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
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Integration
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Limits
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