Solve 41+51+61+71+81+91+1/4+5+6+7+8+9

$$41+51+61+71+81+91+ \frac{ 1 }{ 4+5+6+7+8+9 }$$

Evaluate

$$\frac{15445}{39}\approx 396.025641026$$

Solution Steps

Add 41 and 51 to get 92.

$$92+61+71+81+91+\frac{1}{4+5+6+7+8+9}$$

Add 92 and 61 to get 153.

$$153+71+81+91+\frac{1}{4+5+6+7+8+9}$$

Add 153 and 71 to get 224.

$$224+81+91+\frac{1}{4+5+6+7+8+9}$$

Add 224 and 81 to get 305.

$$305+91+\frac{1}{4+5+6+7+8+9}$$

Add 305 and 91 to get 396.

$$396+\frac{1}{4+5+6+7+8+9}$$

Add 4 and 5 to get 9.

$$396+\frac{1}{9+6+7+8+9}$$

Add 9 and 6 to get 15.

$$396+\frac{1}{15+7+8+9}$$

Add 15 and 7 to get 22.

$$396+\frac{1}{22+8+9}$$

Add 22 and 8 to get 30.

$$396+\frac{1}{30+9}$$

Add 30 and 9 to get 39.

$$396+\frac{1}{39}$$

Convert 396 to fraction \frac{15444}{39}.

$$\frac{15444}{39}+\frac{1}{39}$$

Since \frac{15444}{39} and \frac{1}{39} have the same denominator, add them by adding their numerators.

$$\frac{15444+1}{39}$$

Add 15444 and 1 to get 15445.

$$\frac{15445}{39}$$

Factor

$$\frac{5 \cdot 3089}{3 \cdot 13} = 396\frac{1}{39} = 396.02564102564105$$