Solve 40000+600001/(1.1)^2

$$40000 + 60000 \frac { 1 } { ( 1.1 ) ^ { 2 } }$$

Evaluate

$$\frac{10840000}{121}\approx 89586.776859504$$

Solution Steps

Calculate 1.1 to the power of 2 and get 1.21.

$$40000+60000\times \frac{1}{1.21}$$

Expand \frac{1}{1.21} by multiplying both numerator and the denominator by 100.

$$40000+60000\times \frac{100}{121}$$

Express 60000\times \frac{100}{121} as a single fraction.

$$40000+\frac{60000\times 100}{121}$$

Multiply 60000 and 100 to get 6000000.

$$40000+\frac{6000000}{121}$$

Convert 40000 to fraction \frac{4840000}{121}.

$$\frac{4840000}{121}+\frac{6000000}{121}$$

Since \frac{4840000}{121} and \frac{6000000}{121} have the same denominator, add them by adding their numerators.

$$\frac{4840000+6000000}{121}$$

Add 4840000 and 6000000 to get 10840000.

$$\frac{10840000}{121}$$

Factor

$$\frac{271 \cdot 2 ^ {6} \cdot 5 ^ {4}}{11 ^ {2}} = 89586\frac{94}{121} = 89586.77685950413$$