Solve 40=3*4-x/4-1

$$40= \frac{ 3 \times 4-x }{ 4-1 }$$

Solve for x

$$x=-108$$

Steps for Solving Linear Equation

Multiply 3 and 4 to get 12.

$$40=\frac{12-x}{4-1}$$

Subtract 1 from 4 to get 3.

$$40=\frac{12-x}{3}$$

Divide each term of 12-x by 3 to get 4-\frac{1}{3}x.

$$40=4-\frac{1}{3}x$$

Swap sides so that all variable terms are on the left hand side.

$$4-\frac{1}{3}x=40$$

Subtract 4 from both sides.

$$-\frac{1}{3}x=40-4$$

Subtract 4 from 40 to get 36.

$$-\frac{1}{3}x=36$$

Multiply both sides by -3, the reciprocal of -\frac{1}{3}.

$$x=36\left(-3\right)$$

Multiply 36 and -3 to get -108.

$$x=-108$$