Solve 40+10div60+15div3600

$$40+10 \div 60+15 \div 3600$$

Evaluate

$$\frac{9641}{240}\approx 40.170833333$$

Solution Steps

Reduce the fraction \frac{10}{60} to lowest terms by extracting and canceling out 10.

$$40+\frac{1}{6}+\frac{15}{3600}$$

Convert 40 to fraction \frac{240}{6}.

$$\frac{240}{6}+\frac{1}{6}+\frac{15}{3600}$$

Since \frac{240}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$\frac{240+1}{6}+\frac{15}{3600}$$

Add 240 and 1 to get 241.

$$\frac{241}{6}+\frac{15}{3600}$$

Reduce the fraction \frac{15}{3600} to lowest terms by extracting and canceling out 15.

$$\frac{241}{6}+\frac{1}{240}$$

Least common multiple of 6 and 240 is 240. Convert \frac{241}{6} and \frac{1}{240} to fractions with denominator 240.

$$\frac{9640}{240}+\frac{1}{240}$$

Since \frac{9640}{240} and \frac{1}{240} have the same denominator, add them by adding their numerators.

$$\frac{9640+1}{240}$$

Add 9640 and 1 to get 9641.

$$\frac{9641}{240}$$

Factor

$$\frac{31 \cdot 311}{2 ^ {4} \cdot 3 \cdot 5} = 40\frac{41}{240} = 40.170833333333334$$