Solve 40x-[20-(5-2x)]=3-(-8x-12)

$$40 x - [ 20 - ( 5 - 2 x ) ] = 3 - ( - 8 x - 12 )$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

To find the opposite of 5-2x, find the opposite of each term.

$$40x-\left(20-5-\left(-2x\right)\right)=3-\left(-8x-12\right)$$

The opposite of -2x is 2x.

$$40x-\left(20-5+2x\right)=3-\left(-8x-12\right)$$

Subtract 5 from 20 to get 15.

$$40x-\left(15+2x\right)=3-\left(-8x-12\right)$$

To find the opposite of 15+2x, find the opposite of each term.

$$40x-15-2x=3-\left(-8x-12\right)$$

Combine 40x and -2x to get 38x.

$$38x-15=3-\left(-8x-12\right)$$

To find the opposite of -8x-12, find the opposite of each term.

$$38x-15=3-\left(-8x\right)-\left(-12\right)$$

The opposite of -8x is 8x.

$$38x-15=3+8x-\left(-12\right)$$

The opposite of -12 is 12.

$$38x-15=3+8x+12$$

Add 3 and 12 to get 15.

$$38x-15=15+8x$$

Subtract 8x from both sides.

$$38x-15-8x=15$$

Combine 38x and -8x to get 30x.

$$30x-15=15$$

Add 15 to both sides.

$$30x=15+15$$

Add 15 and 15 to get 30.

$$30x=30$$

Divide both sides by 30.

$$x=\frac{30}{30}$$

Divide 30 by 30 to get 1.

$$x=1$$