Solve 4.9x^2=30

$$4.9 x ^ { 2 } = 30$$

Solve for x

$$x = \frac{10 \sqrt{3}}{7} \approx 2.474358297$$

$$x = -\frac{10 \sqrt{3}}{7} \approx -2.474358297$$

Steps by Finding Square Root

Divide both sides by 4.9.

$$x^{2}=\frac{30}{4.9}$$

Expand \frac{30}{4.9} by multiplying both numerator and the denominator by 10.

$$x^{2}=\frac{300}{49}$$

Take the square root of both sides of the equation.

$$x=\frac{10\sqrt{3}}{7} x=-\frac{10\sqrt{3}}{7}$$

Steps Using the Quadratic Formula

Divide both sides by 4.9.

$$x^{2}=\frac{30}{4.9}$$

Expand \frac{30}{4.9} by multiplying both numerator and the denominator by 10.

$$x^{2}=\frac{300}{49}$$

Subtract \frac{300}{49} from both sides.

$$x^{2}-\frac{300}{49}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{300}{49} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-\frac{300}{49}\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-\frac{300}{49}\right)}}{2}$$

Multiply -4 times -\frac{300}{49}.

$$x=\frac{0±\sqrt{\frac{1200}{49}}}{2}$$

Take the square root of \frac{1200}{49}.

$$x=\frac{0±\frac{20\sqrt{3}}{7}}{2}$$

Now solve the equation x=\frac{0±\frac{20\sqrt{3}}{7}}{2} when ± is plus.

$$x=\frac{10\sqrt{3}}{7}$$

Now solve the equation x=\frac{0±\frac{20\sqrt{3}}{7}}{2} when ± is minus.

$$x=-\frac{10\sqrt{3}}{7}$$

The equation is now solved.

$$x=\frac{10\sqrt{3}}{7} x=-\frac{10\sqrt{3}}{7}$$