Solve 4.1x+8.3y=51.53

$$4.1x+8.3y=51.53$$

Solve for x

$$x=-\frac{83y}{41}+\frac{5153}{410}$$

Steps for Solving Linear Equation

Subtract 8.3y from both sides.

$$4.1x=51.53-8.3y$$

The equation is in standard form.

$$4.1x=-\frac{83y}{10}+51.53$$

Divide both sides of the equation by 4.1, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{4.1x}{4.1}=\frac{-\frac{83y}{10}+51.53}{4.1}$$

Dividing by 4.1 undoes the multiplication by 4.1.

$$x=\frac{-\frac{83y}{10}+51.53}{4.1}$$

Divide 51.53-\frac{83y}{10} by 4.1 by multiplying 51.53-\frac{83y}{10} by the reciprocal of 4.1.

$$x=-\frac{83y}{41}+\frac{5153}{410}$$

Solve for y

$$y=-\frac{41x}{83}+\frac{5153}{830}$$

Steps for Solving Linear Equation

Subtract 4.1x from both sides.

$$8.3y=51.53-4.1x$$

The equation is in standard form.

$$8.3y=-\frac{41x}{10}+51.53$$

Divide both sides of the equation by 8.3, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{8.3y}{8.3}=\frac{-\frac{41x}{10}+51.53}{8.3}$$

Dividing by 8.3 undoes the multiplication by 8.3.

$$y=\frac{-\frac{41x}{10}+51.53}{8.3}$$

Divide 51.53-\frac{41x}{10} by 8.3 by multiplying 51.53-\frac{41x}{10} by the reciprocal of 8.3.

$$y=-\frac{41x}{83}+\frac{5153}{830}$$