Solve 4-3-5+3-32/3/-2

$$4-3-5+ \frac{ 3-3 \frac{ 2 }{ 3 } }{ -2 }$$

Evaluate

$$-\frac{11}{3}\approx -3.666666667$$

Solution Steps

Subtract 3 from 4 to get 1.

$$1-5+\frac{3-\frac{3\times 3+2}{3}}{-2}$$

Subtract 5 from 1 to get -4.

$$-4+\frac{3-\frac{3\times 3+2}{3}}{-2}$$

Multiply 3 and 3 to get 9.

$$-4+\frac{3-\frac{9+2}{3}}{-2}$$

Add 9 and 2 to get 11.

$$-4+\frac{3-\frac{11}{3}}{-2}$$

Convert 3 to fraction \frac{9}{3}.

$$-4+\frac{\frac{9}{3}-\frac{11}{3}}{-2}$$

Since \frac{9}{3} and \frac{11}{3} have the same denominator, subtract them by subtracting their numerators.

$$-4+\frac{\frac{9-11}{3}}{-2}$$

Subtract 11 from 9 to get -2.

$$-4+\frac{-\frac{2}{3}}{-2}$$

Express \frac{-\frac{2}{3}}{-2} as a single fraction.

$$-4+\frac{-2}{3\left(-2\right)}$$

Cancel out -2 in both numerator and denominator.

$$-4+\frac{1}{3}$$

Convert -4 to fraction -\frac{12}{3}.

$$-\frac{12}{3}+\frac{1}{3}$$

Since -\frac{12}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{-12+1}{3}$$

Add -12 and 1 to get -11.

$$-\frac{11}{3}$$

Factor

$$-\frac{11}{3} = -3\frac{2}{3} = -3.6666666666666665$$