Solve 4-2div(7-9)*(-3)+5-4*(2+3

$$4-2 \div (7-9) \times (-3)+5-4 \times (2+3$$

Evaluate

$$-14$$

Solution Steps

Subtract 9 from 7 to get -2.

$$4-\frac{2}{-2}\left(-3\right)+5-4\left(2+3\right)$$

Divide 2 by -2 to get -1.

$$4-\left(-\left(-3\right)\right)+5-4\left(2+3\right)$$

Multiply -1 and -3 to get 3.

$$4-3+5-4\left(2+3\right)$$

Subtract 3 from 4 to get 1.

$$1+5-4\left(2+3\right)$$

Add 1 and 5 to get 6.

$$6-4\left(2+3\right)$$

Add 2 and 3 to get 5.

$$6-4\times 5$$

Multiply 4 and 5 to get 20.

$$6-20$$

Subtract 20 from 6 to get -14.

$$-14$$

Factor

$$-14$$