Solve 4-8/2-x

$$4- \frac{ 8 }{ 2-x }$$

Evaluate

$$-\frac{4x}{2-x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 4 times \frac{2-x}{2-x}.

$$\frac{4\left(2-x\right)}{2-x}-\frac{8}{2-x}$$

Since \frac{4\left(2-x\right)}{2-x} and \frac{8}{2-x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{4\left(2-x\right)-8}{2-x}$$

Do the multiplications in 4\left(2-x\right)-8.

$$\frac{8-4x-8}{2-x}$$

Combine like terms in 8-4x-8.

$$\frac{-4x}{2-x}$$

Factor

$$-\frac{4x}{2-x}$$