Solve for x
x=\frac{5y}{4}+3
Solve for y
y=\frac{4\left(x-3\right)}{5}
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4x=12+5y
Add 5y to both sides.
4x=5y+12
The equation is in standard form.
\frac{4x}{4}=\frac{5y+12}{4}
Divide both sides by 4.
x=\frac{5y+12}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{5y}{4}+3
Divide 12+5y by 4.
-5y=12-4x
Subtract 4x from both sides.
\frac{-5y}{-5}=\frac{12-4x}{-5}
Divide both sides by -5.
y=\frac{12-4x}{-5}
Dividing by -5 undoes the multiplication by -5.
y=\frac{4x-12}{5}
Divide 12-4x by -5.
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