Solve for x
x=\frac{y-4}{2}
Solve for y
y=2\left(x+2\right)
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4x=-8+2y
Add 2y to both sides.
4x=2y-8
The equation is in standard form.
\frac{4x}{4}=\frac{2y-8}{4}
Divide both sides by 4.
x=\frac{2y-8}{4}
Dividing by 4 undoes the multiplication by 4.
x=\frac{y}{2}-2
Divide -8+2y by 4.
-2y=-8-4x
Subtract 4x from both sides.
-2y=-4x-8
The equation is in standard form.
\frac{-2y}{-2}=\frac{-4x-8}{-2}
Divide both sides by -2.
y=\frac{-4x-8}{-2}
Dividing by -2 undoes the multiplication by -2.
y=2x+4
Divide -8-4x by -2.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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