Solve 4x(3/4)^2-4x3/4+1

$$4 x ( \frac { 3 } { 4 } ) ^ { 2 } - 4 x \frac { 3 } { 4 } + 1$$

Evaluate

$$-\frac{3x}{4}+1$$

Solution Steps

Calculate \frac{3}{4} to the power of 2 and get \frac{9}{16}.

$$4x\times \frac{9}{16}-4x\times \frac{3}{4}+1$$

Express 4\times \frac{9}{16} as a single fraction.

$$\frac{4\times 9}{16}x-4x\times \frac{3}{4}+1$$

Multiply 4 and 9 to get 36.

$$\frac{36}{16}x-4x\times \frac{3}{4}+1$$

Reduce the fraction \frac{36}{16} to lowest terms by extracting and canceling out 4.

$$\frac{9}{4}x-4x\times \frac{3}{4}+1$$

Cancel out 4 and 4.

$$\frac{9}{4}x-3x+1$$

Combine \frac{9}{4}x and -3x to get -\frac{3}{4}x.

$$-\frac{3}{4}x+1$$

Factor

$$\frac{4-3x}{4}$$

Solution Steps

Factor out \frac{1}{4}.

$$\frac{9x-12x+4}{4}$$

Consider 9x-12x+4. Multiply and combine like terms.

$$-3x+4$$

Rewrite the complete factored expression.

$$\frac{-3x+4}{4}$$