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x\left(4x^{2}+25x+25\right)
Factor out x.
a+b=25 ab=4\times 25=100
Consider 4x^{2}+25x+25. Factor the expression by grouping. First, the expression needs to be rewritten as 4x^{2}+ax+bx+25. To find a and b, set up a system to be solved.
1,100 2,50 4,25 5,20 10,10
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 100.
1+100=101 2+50=52 4+25=29 5+20=25 10+10=20
Calculate the sum for each pair.
a=5 b=20
The solution is the pair that gives sum 25.
\left(4x^{2}+5x\right)+\left(20x+25\right)
Rewrite 4x^{2}+25x+25 as \left(4x^{2}+5x\right)+\left(20x+25\right).
x\left(4x+5\right)+5\left(4x+5\right)
Factor out x in the first and 5 in the second group.
\left(4x+5\right)\left(x+5\right)
Factor out common term 4x+5 by using distributive property.
x\left(4x+5\right)\left(x+5\right)
Rewrite the complete factored expression.