Solve 4x^2-5y=1

$$4 x ^ { 2 } - 5 y = 1$$

Solve for y

$$y=\frac{4x^{2}-1}{5}$$

Steps for Solving Linear Equation

Subtract 4x^{2} from both sides.

$$-5y=1-4x^{2}$$

Divide both sides by -5.

$$\frac{-5y}{-5}=\frac{1-4x^{2}}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$y=\frac{1-4x^{2}}{-5}$$

Divide -4x^{2}+1 by -5.

$$y=\frac{4x^{2}-1}{5}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{5y+1}}{2}$$

$$x=\frac{\sqrt{5y+1}}{2}$$

Solve for x

$$x=\frac{\sqrt{5y+1}}{2}$$

$$x=-\frac{\sqrt{5y+1}}{2}\text{, }y\geq -\frac{1}{5}$$