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4x^{2}=2
Add 2 to both sides. Anything plus zero gives itself.
x^{2}=\frac{2}{4}
Divide both sides by 4.
x^{2}=\frac{1}{2}
Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.
x=\frac{\sqrt{2}}{2} x=-\frac{\sqrt{2}}{2}
Take the square root of both sides of the equation.
4x^{2}-2=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\times 4\left(-2\right)}}{2\times 4}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 4 for a, 0 for b, and -2 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 4\left(-2\right)}}{2\times 4}
Square 0.
x=\frac{0±\sqrt{-16\left(-2\right)}}{2\times 4}
Multiply -4 times 4.
x=\frac{0±\sqrt{32}}{2\times 4}
Multiply -16 times -2.
x=\frac{0±4\sqrt{2}}{2\times 4}
Take the square root of 32.
x=\frac{0±4\sqrt{2}}{8}
Multiply 2 times 4.
x=\frac{\sqrt{2}}{2}
Now solve the equation x=\frac{0±4\sqrt{2}}{8} when ± is plus.
x=-\frac{\sqrt{2}}{2}
Now solve the equation x=\frac{0±4\sqrt{2}}{8} when ± is minus.
x=\frac{\sqrt{2}}{2} x=-\frac{\sqrt{2}}{2}
The equation is now solved.