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\frac{100x^{2}-9}{25}
Factor out \frac{1}{25}.
\left(10x-3\right)\left(10x+3\right)
Consider 100x^{2}-9. Rewrite 100x^{2}-9 as \left(10x\right)^{2}-3^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(10x-3\right)\left(10x+3\right)}{25}
Rewrite the complete factored expression.